Question

For the following exercises, use the value of the given variable X, and find the value of the variable Y, as it would be with the equation. For the avoidance of doubt: because you have 4 (four) values for X you should repeat all the processes 4 (four) times, once for each value of X.

For X = {5, 8.3, -12, -2}.
A) Y = 3 + X + X², when X = 5, Y = ?
B) Y = 2 * X + 3 - 3X, when X = 8.3, Y = ?
C) Y = X + 2X² - 3X³, when X = -12, Y = ?
D) Y = 2^X, when X = -2, Y = ?

Answer 1

To solve for Y given various values of X, substitute X into the equation and simplify. When X is 5, Y is 33; for X at 8.3, Y is -5.3; for X at -12, Y is 5460; and when X is -2, Y is 0.25.

Step-by-step explanation:

To find the values of Y for each given X using the respective equations, we need to substitute our value of X into the equations and perform the necessary calculations.

1. For X = 5: Y = 3 + X + X²
   Substitute X with 5: Y = 3 + 5 + 5² = 3 + 5 + 25 = 33
2. For X = 8.3: Y = 2 * X + 3 - 3X
   Substitute X with 8.3: Y = 2 * 8.3 + 3 - 3 * 8.3 = 16.6 + 3 - 24.9 = -5.3
3. For X = -12: Y = X + 2X² - 3X³
   Substitute X with -12: Y = -12 + 2 * (-12)² - 3 * (-12)³ = -12 + 2 * 144 - 3 * (-1728) = -12 + 288 + 5184 = 5460
4. For X = -2: Y = 2^X
   Substitute X with -2: Y = 2^-2 = 1/(2^2) = 1/4 = 0.25