Question

How many moles of AlCl3 will be produced if 2.75 moles of Al react?

a) 2.75 moles
b) 1.375 moles
c) 5.50 moles
d) 8.25 moles

Answer 1

The correct answer is 2.75 moles of AlCl3, as the mole ratio between Al and AlCl3 is 1:1 according to the balanced chemical equation 2 Al + 3 Cl2 -> 2 AlCl3.

Step-by-step explanation:

The question involves the stoichiometric calculation of how many moles of AlCl3 (aluminium chloride) will be produced if 2.75 moles of Al (aluminum) react. The balanced chemical equation for the reaction between aluminum and chlorine gas is:

2 Al + 3 Cl₂ → 2 AlCl₃

According to the coefficients in the balanced equation, 2 moles of aluminum (Al) will produce 2 moles of aluminum chloride (AlCl3). Therefore, if we have 2.75 moles of aluminum reacting, it will produce an equal amount of aluminum chloride, because the mole ratio between Al and AlCl3 is 1:1. Hence, the correct answer is 2.75 moles of AlCl3.