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A person is standing on the edge of a merry-go-round that has a radius of 2.0m is travelling at 5m/s. How long does it take for them to complete one lap?

1 Answer

7 votes

Answer:2.51 s

Step-by-step explanation:

Given

The radius of merry-go-round r=2 m

Speed of person at edge v=5 m/s

The person is in a uniform circular motion with constant velocity

time taken to complete one lap is


t=\frac{\text{distance}}{\text{speed}}=(2\pi \cdot 2)/(5)\\\\t=(12.568)/(5)=2.5136\ s

User Anil Ugale
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