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Write the equation in slope-intercept form of a line that has a slope of one-third and passes through the point (-6, 0).

A. y = (1/3)x - 2
B. y = (1/3)x + 2
C. y = 3x - 2
D. y = 3x + 2

User Gattster
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Final answer:

To write the equation of the line, we can use the point-slope form by substituting the given values of the slope and a point on the line. The equation in slope-intercept form is y = (1/3)x + 2.

Step-by-step explanation:

To write the equation of a line in slope-intercept form, we use the equation y = mx + b, where m is the slope and b is the y-intercept. Given that the slope is one-third and the line passes through the point (-6, 0), we can substitute these values into the equation.

Using the point-slope form, we have y - y1 = m(x - x1). Substituting -6 for x1, 0 for y1, and one-third for m, the equation becomes y - 0 = (1/3)(x - (-6)). Simplifying further, y = (1/3)x + 2.

User Ismael Terreno
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