Question

The relationship between voltage, V, current I, and resistance, R is given by the equation V = IR. If the voltage V of the circuit is (8 + 1), and the resistance R is (2 - 1), what is the value of the current I?

Answer 1

According to Ohm's law, the current I in a circuit with a voltage of 9 volts (8 + 1) and a resistance of 1 ohm (2 - 1) is found to be 9 amperes.

Step-by-step explanation:

The relationship between voltage, current, and resistance is defined by Ohm's law as V = IR. To determine the current I, we need to resolve the given expressions for voltage (V = 8 + 1) and resistance (R = 2 - 1).

After simplifying these expressions, we get V = 9 volts (since 8 + 1 = 9) and R = 1 ohm (2 - 1 = 1).

Now we can apply Ohm's law to find the current I. We rearrange the equation to solve for I: I = V/R. Substituting in the known values, we get I = 9V / 1Ω = 9A. Therefore, the value of the current I in the circuit is 9 amperes.