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In the mathematical model y = 720,500(1.022), the number 720,500 represents the initial population of Brownville in January 1980, and the number 1.022 represents the growth rate.

a. To find the population in 2000, you would substitute x = 20 (since it's 20 years after 1980) into the equation: y = 720,500(1.022)^20.
b. To predict when the population will first reach 1,000,000, you would set y = 1,000,000 and solve for x: 1,000,000 = 720,500(1.022)^x.

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Final answer:

To find the population in 2000, substitute x = 20 into the equation y = 720,500(1.022)^20. To predict when the population will reach 1,000,000, set y = 1,000,000 and solve for x: 1,000,000 = 720,500(1.022)^x.

Step-by-step explanation:

To find the population in 2000, you would substitute x = 20 (since it's 20 years after 1980) into the equation: y = 720,500(1.022)^20. This will give you the population of Brownville in the year 2000.

To predict when the population will first reach 1,000,000, you would set y = 1,000,000 and solve for x: 1,000,000 = 720,500(1.022)^x. This will give you the number of years it will take for the population to reach 1,000,000.

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