Final answer:
The point-slope form of the equation of the line that is parallel to y = -2x - 6 and passes through the point (-3, 11) is y = -2x + 5.
Step-by-step explanation:
The point-slope form of the equation of a line is given by y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope of the line.
The slope of the given line y = -2x - 6 is -2. Since the line we want is parallel to this line, it will have the same slope. So, the slope (m) of the line we want is -2.
Using the point (-3, 11) and the slope -2, we can substitute these values into the point-slope form to find the equation of the line:
y - 11 = -2(x - (-3))
y - 11 = -2(x + 3)
y - 11 = -2x - 6
y = -2x + 5
Therefore, the point-slope form of the equation of the line that is parallel to y = -2x - 6 and passes through the point (-3, 11) is y = -2x + 5.