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12. If you were to spin the spinner 10 times, and it happened to land on a "2" six times, a "1" three

times, and on a "3" one time, what would the experimental probability be that you would have
landed on a "1"?
13. Given the same scenario in problem #12, what would the experimental probability be that your
would have landed on a "4"?

User Samsinite
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1 Answer

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The experimental probability that the spinner landed on "1" is 30%. The experimental probability of landing on "4", given the scenario with no such occurrences, is 0%. Experimental probability is based on actual outcomes and may differ from theoretical probability, which is based on possible outcomes.

The experimental probability of an event is calculated by dividing the number of times the event occurs by the total number of trials. Given that the spinner landed on "1" three times out of 10 spins, we calculate the experimental probability by dividing 3 (the number of times it landed on "1") by 10 (the total number of spins).

Experimental Probability of landing on "1": Probability = Number of times landing on "1" / Total number of spins = 3/10 = 0.3 or 30%.

For problem #13, since there is no mention of the spinner landing on "4", we assume it did not occur in the 10 spins. Therefore, the experimental probability of landing on "4" in this scenario would be 0/10 = 0 or 0%.

It's important to note that while experimental probability is based on actual outcomes, theoretical probability is based on the possible outcomes before the experiment is conducted. In case of a fair spinner with numbers 1 through 4, the theoretical probability would be 1/4 or 25% for each number. However, experimental probability can vary from the theoretical probability, especially with a small number of trials.

User AndHeiberg
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