Question

The velocity of a car increases from 4 m/s at 2 sec. To 32 m/s at 9 sec. What is the car’s average acceleration?

Answer 1

`a=4\ m/s^2`

Explanation:

Given that,

The velocity of a car increases from 4 m/s at 2 sec to 32 m/s at 9 sec.

We need to find the car's average acceleration. It can be given by the change in velocity divided by the change in time. So,

`a=(v-u)/(t_2-t_1)\\\\a=(32-4)/(9-2)\\\\a=4\ m/s^2`

So, the car's average acceleration is equal to
`4\ m/s^2`.