Final answer:
The elastic constant of the spring is 2.08 N/m and the body weight is 0.098 N.a. So, the correct option is a. Elastic constant = 2.08 N/m, Body weight = 0.098 N
Step-by-step explanation:
To find the elastic constant of the spring, we can use Hooke's Law which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.
The equation for Hooke's Law is F = kx, where F is the force, k is the elastic constant, and x is the displacement.
In this case, the mass of the body is 0.01 kg and it stretches the spring by 4.8 mm (which is equivalent to 0.0048 m).
Therefore, we can rearrange the equation to solve for the elastic constant: k = F / x.
The force can be calculated using the formula F = mg, where m is the mass and g is the acceleration due to gravity.
Plugging in the values, we get: k = (0.01 kg * 9.8 m/s^2) / 0.0048 m = 2.08 N/m.
The body weight can also be calculated using the formula F = mg: F = 0.01 kg * 9.8 m/s^2 = 0.098 N.
Therefore, the correct option is a. Elastic constant = 2.08 N/m, Body weight = 0.098 N