Question

How many types of atoms are in this equation 2KOH + CO2 = K2CO3 + H2O?

A) 2
B) 3
C) 4
D) 5

Answer 1

The equation 2KOH + CO2 = K2CO3 + H2O contains four distinct types of atoms: potassium (K), oxygen (O), hydrogen (H), and carbon (C), making the correct answer C) 4.

Step-by-step explanation:

To determine the number of different types of atoms in the equation 2KOH + CO2 = K2CO3 + H2O, we need to identify each distinct element present. In the reactants, we have potassium (K), oxygen (O), hydrogen (H), and carbon (C). The products also contain these same elements. Therefore, the total number of distinct atom types is:

• Potassium (K)
• Oxygen (O)
• Hydrogen (H)
• Carbon (C)

The correct answer to the question is C) 4.