Question

A 5.50 kg box is pushed across the lunch table. The net force applied to the box is 9.70N. What is the acceleration of the box?

A) 1.76
B) 1.76 m/s²
C) 5.50
D) 5.50 m/s²

Answer 1

The acceleration of the 5.50 kg box being pushed by a net force of 9.70 N is 1.76 m/s², so the correct answer is B) 1.76 m/s².

Step-by-step explanation:

The acceleration of the 5.50 kg box can be calculated using Newton's second law of motion, which states that the force (F) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a), expressed as F = m × a. To find the acceleration, you rearrange the formula to a = F / m.

In this case, you have a net force of 9.70 N acting on a mass of 5.50 kg. The acceleration (a) is therefore calculated as follows:

a = F / m = 9.70 N / 5.50 kg = 1.76 m/s²

The correct answer to the question is B) 1.76 m/s².