Question

What are the coordinates of the center of a circle with an equation of (x - 3)^2 + (y + 7)^2 = 120^2?

a. (3, -7)
b. (-3, 7)
c. (3, 7)
d. (-3, -7)

Answer 1

The coordinates of the center of the circle given by the equation (x - 3)^2 + (y + 7)^2 = 120^2 are (3, -7).

Step-by-step explanation:

The equation of the circle, given by (x - 3)^2 + (y + 7)^2 = 120^2, is in the standard form of a circle (x - h)^2 + (y - k)^2 = r^2, where (h, k) are the coordinates of the center of the circle and r is the radius. Comparing it to the given equation, the center of the circle is at (3, -7), which corresponds to option a. (3, -7).