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The coefficient of sliding friction on a surface is 0.3. A box requires 300 N to slide it across the surface with constant velocity. What is the weight of the box?

A. 300 N
B. 100 N
C. 900 N
D. 600 N

1 Answer

5 votes

Final answer:

Using the coefficient of sliding friction (0.3) and the force to slide the box (300 N), the normal force, which is equal to the weight, should be 1000 N, indicating a possible error in the question or given options.

Step-by-step explanation:

The question asks us to find the weight of a box knowing that the coefficient of sliding friction on a surface is 0.3 and a force of 300 N is required to slide it across the surface with constant velocity. The force required to slide the box at constant velocity is equal to the frictional force, which can be calculated using the formula Ffriction = μk × N, where μk is the coefficient of kinetic friction and N is the normal force, which is equal to the weight of the box (W) in this case since the surface is horizontal. Thus, 300 N = 0.3 × W, and solving for W gives us W = 300 N / 0.3 = 1000 N. However, since this value is not one of the choices and it is given that N is the weight, the closest option is D, which signifies a potential error in either the question or the options provided.

User Benjamin Du
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