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If the horse lifts a 50 kilogram mass a vertical distance of 3 meters in 2 seconds, what is the horse’s minimum power output?

T= 2s
d= 3s
m= 50kg

User Peyton
by
3.6k points

1 Answer

7 votes

Answer:

735watts

Step-by-step explanation:

Power = Force*distance/time

Given

Force = mg = 50 * 9.8'

Force = 490N

distance = 3m

time = 2s

Substitute

Power = 490*3/2

Power = 1470/2

Power = 735Watts

Hence the minimum power output is 735watts

User Christin
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3.4k points