Question

Given (log_5(3)=m) and (log_6(45)=n), express (log_3(2)) in terms of (m) and (n).

a) 2/m - n/3
b) 1/m + 2n/3
c) (1/m + n/3
d) 2/m + 2n/3

Answer 1

To express log_3(2) in terms of m and n, we can use the properties of logarithms. The expression is log_5(2) / m.

Step-by-step explanation:

To express log3(2) in terms of m and n, we can use the properties of logarithms. First, recall that loga(b) is equal to logc(b) / logc(a). Applying this property, we have:

log3(2) = log5(2) / log5(3)

Since we were given that log5(3) = m, we can substitute it into the equation:

log3(2) = log5(2) / m

Therefore, the expression for log3(2) in terms of m and n is log5(2) / m.