Question

Write an equation that represents the following sentence and solve: Find three consecutive integers whose sum is the square of 6.

a. n+(n+1)+(n+2)=6^2 ; Solve for n.
b. 3n=6^2 ; Solve for n.
c. n^2+6=3 ; Solve for n.
d.n^3 +(n+1)^3 +(n+2)^3 =6^2 ; Solve for n.

Answer 1

The correct equation is n + (n + 1) + (n + 2) = 6^2, which simplifies to 3n + 3 = 36. When solved for n, the answer is 11, resulting in three consecutive integers: 11, 12, and 13.

Step-by-step explanation:

The equation that represents the sentence 'Find three consecutive integers whose sum is the square of 6' is n + (n + 1) + (n + 2) = 6^2. To solve for n, we combine like terms and get 3n + 3 = 36. We then subtract 3 from both sides, resulting in 3n = 33. Finally, we divide both sides by 3 to find that n = 11.

So the three consecutive integers are 11, 12, and 13.