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What is the equation of the line passing through the points (11, -3) and (7, 9)?

A) y = -3x + 24
B) y = 3x + 24
C) y = -3x - 24
D) y = 3x - 24

User Alessmar
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1 Answer

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Final answer:

The equation of the line passing through the points (11, -3) and (7, 9) is y = -3x + 30.

Step-by-step explanation:

To find the equation of a line passing through two given points, we can use the slope-intercept form of a linear equation, which is y = mx + b. The slope (m) of the line can be found using the equation: m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are the coordinates of the two points.

Using the given points (11, -3) and (7, 9), we can find the slope as follows:

m = (9 - (-3)) / (7 - 11)

m = 12 / (-4) = -3

Now, we can substitute one of the points and the slope into the equation y = mx + b to find the y-intercept (b). Let's use the first point (11, -3):

-3 = -3(11) + b

-3 = -33 + b

b = -3 + 33 = 30

Therefore, the equation of the line passing through the points (11, -3) and (7, 9) is y = -3x + 30.

User Miguel Garrido
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