Question

The aquarium is advertised as being able to hold a maximum of 65 gallons of water as the aquarium is not meant to be completely filled with water. Assume Alex fills the aquarium to its maximum capacity. Based on the dimensions of the aquarium, what percent of the aquarium should not be filled with water? Round your answer to the nearest whole percent.

A) 13%
B) 20%
C) 8%
D) 5%

Answer 1

The percent of the aquarium that should not be filled with water is 50%, which is not an option.

Step-by-step explanation:

To find the percent of the aquarium that should not be filled with water, we need to consider the maximum capacity of the aquarium and its dimensions. Let's assume that the dimensions of the aquarium are length (L), width (W), and height (H).

The volume of the aquarium is given by V = L * W * H. If the maximum capacity is 65 gallons, then we can convert this to liters, since the density of water is 1 g/mL or 1 L/1000 mL:

65 gallons * 3.78541 L/gallon = 246.12565 L

Now, let's assume the aquarium is filled completely with water. If the percentage of water to be filled is x%, then the volume of water in liters is given by:

Volume of water = (x/100) * 246.12565 L

Since the aquarium is not meant to be completely filled, the remaining volume should be (100-x)% of the maximum capacity. Therefore, the volume of the remaining space in liters is given by:

Volume of remaining space = (100-x)/100 * 246.12565 L

Now, we can equate the volume of water and the volume of remaining space:

(x/100) * 246.12565 L = (100-x)/100 * 246.12565 L

Simplifying the equation, we get:

x = 100 - x

2x = 100

x = 50

Therefore, 50% of the aquarium should be filled with water, and the remaining 50% should not be filled with water. Rounded to the nearest whole percent, the answer is 50%.