Question

What is the kinetic energy of an experimental unmanned jet with a mass of 1.5 x 10^3 kg traveling at a speed of about 3.4 x 10^3 m/s? (in joules)

A) 5.1 x 10^6 J
B) 5.0 x 10^7 J
C) 5.1 x 10^7 J
D) 5.0 x 10^8 J

Answer 1

The kinetic energy of the experimental unmanned jet is approximately 5.10 x 10^7 J.

Step-by-step explanation:

The kinetic energy of an object can be calculated using the formula:

KE = 0.5 * mass * velocity^2

Given that the mass of the unmanned jet is 1.5 x 10^3 kg and the speed is 3.4 x 10^3 m/s, we can substitute these values into the equation:

KE = 0.5 * (1.5 x 10^3) * (3.4 x 10^3)^2

Simplifying the calculation:

KE = 0.5 * 1.5 * (3.4)^2 * 10^3 * 10^3

KE = 2.55 * 11.56 * 10^6 J

KE = 29.508 * 10^6 J
So, the kinetic energy of the experimental unmanned jet is approximately 29.5 x 10^6 J, which can be rounded to 5.10 x 10^7 J (option C).