Question

Given the following information:

8.81 g Carbon
91.2 g Chlorine
Molar Mass: 1362.5 g/mol
Find the empirical formula and the molecular formula.

A. Empirical formula: CCl3, Molecular formula: C6Cl18
B. Empirical formula: CCl2, Molecular formula: C4Cl8
C. Empirical formula: CCl4, Molecular formula: C4Cl16
D. Empirical formula: C2Cl4, Molecular formula: C4Cl8

Answer 1

The empirical formula is CCl4 and the molecular formula is C4Cl16.

Step-by-step explanation:

To find the empirical formula, we need to determine the ratio of atoms in the compound. First, we calculate the moles of each element from their given masses using the molar mass. The moles are then divided by the smallest mole value to get the simplest whole-number ratio. In this case, the empirical formula is CCl4.

To find the molecular formula, we compare the molar mass of the empirical formula to the given molar mass of the compound. The molecular formula would be a multiple of the empirical formula. In this case, the molecular mass is consistent with C4Cl16. Therefore, the correct options are Empirical formula: CCl4, Molecular formula: C4Cl16.