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Using 3.14 for 11, what is the volume to the nearest tenth of a cone that has a helght of 17 meters and a

base with a radius of 6 meters?

User Fundead
by
5.7k points

1 Answer

5 votes

Answer:

904.9m^3

Explanation:

Given data

h= 17 m

r= 6 m

V= 4/3πr^3

substitute

V= 4/3*3.142*6^3

v=4*3.142*216/3

v=2714.688/3

v= 904.9m^3

Hence the volume is 904.9m^3

User Adam Richardson
by
5.7k points