Question

Enter the number of complex zeros for the polynomial function in the box.

a) 0
b) 1
c) 2
d) 3

Answer 1

The given polynomial function has two real zeros.

Step-by-step explanation:

The given polynomial function is x²+1.2x10-2x-6.0×10-³ = 0. To determine the number of complex zeros, we can look at the discriminant of the quadratic equation. The discriminant, symbolized by delta (Δ), is given by the formula Δ = b²-4ac. If Δ < 0, there are two complex zeros. If Δ = 0, there is one complex zero. If Δ > 0, there are two real zeros.

For the given polynomial function, a = 1.00, b = 1.2x10-2, and c = -6.0x10-³. Substituting these values into the discriminant formula, we get Δ = (1.2x10-2)² - 4(1.00)(-6.0x10-³).

Simplifying, we have Δ = 1.44x10-4 + 2.4x10-² = 2.4x10-² (approx).

Since Δ > 0, there are two real zeros for the polynomial function.