Question

What is the equation in slope-intercept form of the line that passes through the points (-2.5, -6) and (7, 13)?

A. y = 2x + 4
B. y = 2x - 4
C. y = -2x + 4
D. y = -2x - 4

Answer 1

The equation in slope-intercept form of the line that passes through the points (-2.5, -6) and (7, 13) is y = 2x - 1.

Step-by-step explanation:

To find the equation of the line in slope-intercept form, we first need to find the slope of the line.

Using the formula for slope, which is given by:

slope = (y2 - y1) / (x2 - x1)

Substituting the coordinates of the given points:

slope = (13 - (-6)) / (7 - (-2.5)) = 19 / 9.5 = 2

Now that we have the slope, we can use the slope-intercept form of a line, which is given by:

y = mx + b

Substituting the slope and the coordinates of one of the points:

-6 = 2(-2.5) + b

-6 = -5 + b

b = -1

So, the equation in slope-intercept form of the line that passes through the points (-2.5, -6) and (7, 13) is y = 2x - 1.