Final answer:
The minimum stopping distance for a car initially traveling at 43.50 m/s and decelerating at 6.70 m/s² is calculated using the equation d = v² / (2a), resulting in a stopping distance of 141.21 meters. The provided options do not match this calculation.
Step-by-step explanation:
To determine the minimum stopping distance of a car initially traveling at 43.50 m/s and decelerating at a rate of 6.70 m/s², we can use the kinematic equation for uniformly accelerated motion:
d = v² / (2a) where d is the stopping distance, v is the initial velocity, and a is the deceleration.
Plugging the values into the equation gives us:
d = (43.50 m/s)² / (2 × 6.70 m/s²)
d = 1892.25 m²/s² / 13.4 m/s²
d = 141.21 meters
However, none of the options A to D match this calculation. There might be a misunderstanding in the options provided. But according to our calculation, the stopping distance is 141.21 meters assuming no initial reaction time delay.