Final answer:
The pressure required to compress a 1 L volume of air at 1 atm pressure to 0.5 L is 2.00 atm.
Step-by-step explanation:
To calculate the final pressure required to compress a 1 L volume of air at 1 atm pressure to 0.5 L, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.
According to Boyle's Law:
P1 * V1 = P2 * V2
Where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
Given: P1 = 1 atm, V1 = 1 L, V2 = 0.5 L
Plugging these values into the formula:
1 atm * 1 L = P2 * 0.5 L
P2 = (1 atm * 1 L) / 0.5 L = 2 atm
Therefore, the amount of pressure required to compress the 1 L volume of air to 0.5 L is 2.00 atm, which matches option c.