Question

Solution #3 is 100.0 mL of a 0.100 M CuSO4 prepared by diluting the 0.250 M CuSO4 stock solution prepared in Part A. Begin by identifying each quantity below.

Cstock = Cdilute = Vdilute =

a) Cstock = 0.250 M, Cdilute = 0.100 M, Vdilute = 100.0 mL
b) Cstock = 0.100 M, Cdilute = 0.250 M, Vdilute = 100.0 mL
c) Cstock = 0.250 M, Cdilute = 0.100 M, Vdilute = 250.0 mL
d) Cstock = 0.100 M, Cdilute = 0.250 M, Vdilute = 250.0 mL

Answer 1

The quantities for the diluted CuSO4 solution are identified as Cstock = 0.250 M, Cdilute = 0.100 M, Vdilute = 100.0 mL.

Step-by-step explanation:

The subject of this question is Chemistry and the grade level is High School.

The given question is asking for the identification of various quantities in solution #3, which is a diluted solution of CuSO4. The options provided are:

• a) Cstock = 0.250 M, Cdilute = 0.100 M, Vdilute = 100.0 mL
• b) Cstock = 0.100 M, Cdilute = 0.250 M, Vdilute = 100.0 mL
• c) Cstock = 0.250 M, Cdilute = 0.100 M, Vdilute = 250.0 mL
• d) Cstock = 0.100 M, Cdilute = 0.250 M, Vdilute = 250.0 mL

The correct answer is option a) Cstock = 0.250 M, Cdilute = 0.100 M, Vdilute = 100.0 mL. This is because the solution #3 is prepared by diluting the 0.250 M CuSO4 stock solution to a final volume of 100.0 mL, resulting in a concentration of 0.100 M.