Question

What are the zeros of f(x) = x2 + x - 12?

O A. x= -4 and x = 3
O B. x=-2 and x = 6
O C. =-3 and x = 4
O D. X=-6 and x = 2

Answer 1

(x+4)(x-3) or A

Explanation:

I'm going to assume that you meant to write x² and not x2

which means we have

x²+x-12

and we need to factor this

to do this we need two numbers that add up to 1 (b) but mulitply to -12 (a*c)

our two numbers are

4, -3

Which means the answer is

(x+4)(x-3)

Answer 2

`{ \large{ \bf{f(x) = x {}^(2) + x - 12}}}`

`{ \large{ \bf{zeros = \frac{ - b± \sqrt{b {}^(2) - 4ac } }{2a} }}}`

`{ \large{ \bf{zeros = \frac{ - 1± \sqrt{1 {}^{} + 48 } }{2} }}}`

`{ \large{ \bf{zeros = ( -1± 7 )/(2) }}}`

`{ \large{ \bf{➢ \: \: zeros = - 4 \: \: and \: 3 }}} \: \: \: \: \: \: (ans)`

Opt A.) is the answer