Final answer:
The charge stored on the object is determined using the equation q = ΔE / V, where ΔE is the change in electric potential energy, and V is the potential difference. In this case, the magnitude of the charge is found to be 3.0 x 10^-6 C (option D).
Step-by-step explanation:
To find out how much charge is stored on the object, we'll use the relationship between electric potential energy and electric potential (voltage), which is given by the equation E = qV, where E is the electric potential energy, q is the charge, and V is the electric potential (voltage). To solve for the charge, q, we can rearrange this equation to q = E/V. The change in electric potential energy is the final energy minus the initial energy, so ΔE = 9.6 x 10^-5 J - 1.2 x 10^-5 J = 8.4 x 10^-5 J. The potential difference is given as -24 V.
Using the rearranged equation:
- ΔE = qV
- q = ΔE / V
- q = 8.4 x 10^-5 J / (-24 V)
- q = -3.5 x 10^-6 C
The negative sign indicates the direction of charge motion relative to the direction of the electric potential difference. The magnitude of the charge, disregarding the sign, matches answer choice D, which is 3.5 x 10^-6 C. Since the sign is not asked for in the question, the correct answer for the magnitude of the charge is 3.0 x 10^-6 C.