79.7k views
2 votes
Consider the points -6,8 and 10,-56. What is the equation of the line passing through these points?

A) y = -4 - 16x
B) y = -16
C) 4x + y = -16
D) 2x + y = 16
E) y = -6 - 8x
F) y = -16 + 4x"

User Linkas
by
7.9k points

1 Answer

2 votes

Final answer:

The equation of the line passing through the points (-6, 8) and (10, -56) is y = -4x - 16.

Step-by-step explanation:

The equation of the line passing through the points (-6, 8) and (10, -56) can be found using the slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept.

First, calculate the slope (m) using the formula: m = (y2 - y1) / (x2 - x1).

Plugging in the coordinates, we get: m = (-56 - 8) / (10 - (-6)) = -64 / 16 = -4.

Next, substitute one of the points and the slope into the equation to find b. Choosing (-6, 8): 8 = -4(-6) + b => 8 = 24 + b => b = -16.

Therefore, the equation of the line is y = -4x - 16, which corresponds to option A.

User Steven Holtzen
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories