Question

Consider the points -6,8 and 10,-56. What is the equation of the line passing through these points?

A) y = -4 - 16x
B) y = -16
C) 4x + y = -16
D) 2x + y = 16
E) y = -6 - 8x
F) y = -16 + 4x"

Answer 1

The equation of the line passing through the points (-6, 8) and (10, -56) is y = -4x - 16.

Step-by-step explanation:

The equation of the line passing through the points (-6, 8) and (10, -56) can be found using the slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept.

First, calculate the slope (m) using the formula: m = (y2 - y1) / (x2 - x1).

Plugging in the coordinates, we get: m = (-56 - 8) / (10 - (-6)) = -64 / 16 = -4.

Next, substitute one of the points and the slope into the equation to find b. Choosing (-6, 8): 8 = -4(-6) + b => 8 = 24 + b => b = -16.

Therefore, the equation of the line is y = -4x - 16, which corresponds to option A.