Question

An elastic band is stretched from 1m to 1.8m. It has a spring constant of 0.5N/m. Calculate the force applied.

a) 0.45 N
b) 0.9 N
c) 0.18 N
d) 0.225 N

Answer 1

Using Hooke's Law, the force applied to stretch an elastic band with a spring constant of 0.5N/m from 1m to 1.8m is 0.4N. The given options do not list the correct answer.

Step-by-step explanation:

To calculate the force applied to an elastic band using Hooke's Law, which states that the force (F) needed to stretch or compress a spring by some distance (x) is directly proportional to that distance. That is, F = kx, where k is the spring constant and x is the extension or compression of the spring. Here, the elastic band is extended from 1m to 1.8m, meaning the extension is 0.8m (1.8m - 1m). With a spring constant (k) of 0.5N/m, the force applied can be calculated as:

F = kx = 0.5N/m × 0.8m = 0.4N

The correct answer is not listed among the given options, as the calculated force is 0.4N.