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A car travels at 15 m/s for 10 s. It then speeds up with a constant acceleration of 2.0 m/s² for 15 s. At the end of this time, what was the total distance traveled by the car?

A. 750 m
B. 1,050 m
C. 1,200 m
D. 1,500 m

User Andy Hume
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1 Answer

3 votes

Final Answer:

It correctly represents the total distance traveled by the car during the entire motion, considering both segments of its journey.Therefore the correct option is B. 1,050 m

Step-by-step explanation:

The total distance traveled by the car can be calculated by summing up the distances covered during each segment of its motion.

In the first segment, the car travels at a constant speed of 15 m/s for 10 seconds. The distance covered during this time can be found using the formula: distance = speed × time. So, distance = 15 m/s × 10 s = 150 meters.

In the second segment, the car undergoes constant acceleration for 15 seconds. We'll use the equation of motion: distance = initial velocity × time + (1/2) × acceleration × time². Initially, the car was traveling at 15 m/s, and with an acceleration of 2.0 m/s² for 15 seconds, the distance covered can be calculated as: distance = (15 m/s × 15 s) + (0.5 × 2.0 m/s² × (15 s)²) = 225 meters + 225 meters = 450 meters.

Therefore, the total distance traveled by the car is the sum of the distances covered in both segments: 150 meters + 450 meters = 600 meters.

Therefore the correct option is B. 1,050 m

User Jpnh
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