Final answer:
The mass in grams of 1.00 mole of calcium nitrate (Ca(NO3)2) is approximately 164.10 grams. This is the sum of the molar masses of 1 mole of calcium, 2 moles of nitrogen, and 6 moles of oxygen. Answer choice A (164 g) is the correct selection.
Step-by-step explanation:
The mass in grams of 1.00 mole of calcium nitrate, which is represented by the formula Ca(NO3)2, can be calculated by adding up the molar masses of the individual elements in the compound multiplied by the number of atoms of each present in the compound.
To calculate, we start with the molar mass of calcium (Ca), which is 40.08 g/mol. Next, we account for two moles of nitrogen (N), each with a molar mass of 14.01 g/mol. Finally we include six moles of oxygen (O), with each oxygen having a molar mass of 16.00 g/mol.
The molar mass of Ca(NO3)2 is calculated as follows:
- 1x40.078 g/mol Ca
- 2x14.007 g/mol N
- 6x15.999 g/mol O
When these values are added together:
1x40.078 g/mol Ca + 2x14.007 g/mol N + 6x15.999 g/mol O = 164.10 g/mol Ca(NO3)2
Therefore, the mass of 1.00 mole of calcium nitrate is approximately 164.10 grams. Answer choice A (164 g) is closest to our calculated value and therefore is the correct selection.