Question

During an intense game of croquet, a 0.52-kg ball at rest on the grass is struck by a mallet with an average force of 220 N. If the mallet is in contact with the ball for 7.2 x 10^-3 seconds, what is the ball’s speed just after it is hit? Express your answer to two significant figures and include the appropriate units.

a) 0.07 m/s
b) 1.43 m/s
c) 1.9 m/s
d) 0.01 m/s

Answer 1

To find the ball's speed just after it is hit, we can use the equation: Force = mass x acceleration. Rearranging the equation, we get Acceleration = Force/mass. Plugging in the given values and calculating, we find that the ball's speed just after it is hit is 3.05 m/s.

Step-by-step explanation:

To find the ball's speed just after it is hit, we can use the equation:

Force = mass x acceleration

First, we need to find the acceleration. We can use the equation:

Force = mass x acceleration

Rearranging the equation, we get:

Acceleration = Force/mass

Now, we can substitute the given values into the equation:

Acceleration = 220 N / 0.52 kg = 423.08 m/s²

Next, we can use the equation:

Final velocity = Initial velocity + (acceleration x time)

The initial velocity is 0 m/s since the ball is at rest. Plugging in the values, we get:

Final velocity = 0 m/s + (423.08 m/s² x 7.2 x 10^-3 s) = 3.05 m/s

Therefore, the ball's speed just after it is hit is 3.05 m/s.