Question

Write a function in recursive form for the arithmetic function where the first term is 14 and the common difference is 1/2.

a) f(0) = 14, f(n) = f(n-1) + 1/2
b) f(0) = 14, f(n) = f(n-1) - 1/2
c) f(1) = 14, f(n) = f(n-1) + 1/2
d) f(1) = 14, f(n) = f(n-1) - 1/2

Answer 1

The recursive form for the arithmetic function with a first term of 14 and a common difference of 1/2 is f(0) = 14, f(n) = f(n-1) + 1/2.

Step-by-step explanation:

The recursive form for the arithmetic function with a first term of 14 and a common difference of 1/2 can be written as:

1. f(0) = 14, f(n) = f(n-1) + 1/2
2. f(0) = 14, f(n) = f(n-1) - 1/2
3. f(1) = 14, f(n) = f(n-1) + 1/2
4. f(1) = 14, f(n) = f(n-1) - 1/2

The correct function is option a) f(0) = 14, f(n) = f(n-1) + 1/2.