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What is the principal root of 3√(-216/729)?

a) A. -6/9
b) B. 6/9
c) C. -36/81
d) D. 36/81

1 Answer

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Final answer:

The principal root of 3√(-216/729) is simplified to -2/3 which is equivalent to -6/9, matching the option (A) -6/9.

Step-by-step explanation:

To find the principal root of the cube root section of the expression 3√(-216/729), we first simplify the fraction inside the cube root.

-216 divided by 729 simplifies to -8/27 because both numbers are divisible by 27.

Taking the cube root of -8/27 gives us -2/3 because the cube root of -8 is -2 and the cube root of 27 is 3.

Therefore, the correct answer is -2/3, which is equivalent to -6/9 after multiplying the numerator and denominator by 3 to match the options provided. The correct answer is represented by option (A) -6/9.

User Rudolf Manusachi
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