Final answer:
The amount of zinc chloride produced can be determined by calculating the number of moles of each reactant and using the mole ratio from the balanced equation. The answer is c) 19.0 grams.
Step-by-step explanation:
In order to determine how much zinc chloride is produced by adding 9.5 grams of zinc and 9.5 grams of HCl, we first need to determine the limiting reactant. We can do this by calculating the number of moles of each reactant using their molar masses.
The molar mass of zinc (Zn) is 65.38 g/mol, so 9.5 grams of zinc is equivalent to 9.5 / 65.38 = 0.1453 moles of zinc.
The molar mass of hydrochloric acid (HCl) is 36.46 g/mol, so 9.5 grams of HCl is equivalent to 9.5 / 36.46 = 0.2601 moles of HCl.
Since the balanced equation for the reaction is Zn + 2HCl → ZnCl₂ + H₂, we can see that the mole ratio between zinc and zinc chloride is 1:1. This means that 0.1453 moles of zinc will produce 0.1453 moles of zinc chloride.
Therefore, the answer is c) 19.0 grams of zinc chloride.