Question

Example: Find four consecutive odd integers whose sum is -80.

An odd integer can be written as 2n+1, where n is any integer. if 2n + 1 the first odd integer, then add 2 to get the next largest odd integer, and so on.

Now write an equation to solve this problem.

(2n+1)+(2n+3)+(2n+5)+(2n+7)=−80

Exercises:

Complete the solution to the problem in the example.
a) n=−9
b) n=−10
c) n=−8
d) n=−7

Answer 1

To find four consecutive odd integers whose sum is -80, set up an equation and solve for x. The four consecutive odd integers are -23, -21, -19, and -17.

Step-by-step explanation:

To find four consecutive odd integers whose sum is -80, we can set up an equation. Let's call the first odd integer x. The next three consecutive odd integers would be x+2, x+4, and x+6. The sum of these four integers is -80, so the equation is: x + (x+2) + (x+4) + (x+6) = -80.

We can simplify the equation by combining like terms: 4x + 12 = -80.

Next, we can subtract 12 from both sides of the equation: 4x = -92.

Finally, we divide both sides of the equation by 4 to solve for x: x = -23.

The four consecutive odd integers are -23, -21, -19, and -17.