215k views
5 votes
Solve the equation V^2 + 2V - 8 = 0 using the quadratic formula. What are the solutions for V?

A) V = 2 and V = -4
B) V = 4 and V = -2
C) V = 2 and V = 4
D) V = -2 and V = -4

1 Answer

3 votes

Final answer:

The quadratic equation V² + 2V - 8 = 0 can be solved using the quadratic formula to obtain the solutions V = 2 and V = -4.

Step-by-step explanation:

This expression is a quadratic equation of the form at² + bt + c = 0, where the constants are a = 1, b = 2, and c = -8. To solve the equation, we can use the quadratic formula V = (-b ± √(b² - 4ac))/(2a).

Substituting the values of a, b, and c into the formula, we get:

V = (-2 ± √(2² - 4(1)(-8)))/(2(1))

Simplifying further:

V = (-2 ± √(4 + 32))/(2)

V = (-2 ± √(36))/(2)

V = (-2 ± 6)/(2)

Therefore, the solutions for V are V = 2 and V = -4. Therefore, the answer is A) V = 2 and V = -4.

User Nethsix
by
8.0k points