Final answer:
The volume of oxygen formed from the decomposition of 5.0 L of water vapor, under the same conditions of temperature and pressure, would be 2.5 L.
Step-by-step explanation:
When decomposing water vapor into hydrogen and oxygen, the balanced chemical reaction is 2H₂(g) + O₂(g) → 2H₂O(g). This means that two volumes of hydrogen gas react with one volume of oxygen gas to produce two volumes of water vapor. If we start with 5.0 L of water vapor, keeping in mind the stoichiometry of the reaction, we would have half that volume of oxygen gas since water produces oxygen and hydrogen in a 2:1 ratio. Therefore, the correct volume of oxygen that would form under the same conditions of temperature and pressure would be half of the water vapor volume, which is .