Question

Hi, can anyone please help with this? I'm having a very hard time with this specific problem plus math is my least strong subject and it would mean so much if someone could help. Thank you!!

Answer 1

Explanation:

For reference the quadratic equations looks like this

(-b±
`√(b^2-(4*a*c))\\`)/2a

Amy's mistake (and solution)

We can see that when amy mulitplied c she wrote 20 instead of -20 (in step 1). She can fix this by writing (4*1*-20) instead

Richard's mistake (and solution)

When richard messed up on step 5 when he wrote (6-2i)/2. You only would write the i if the negative was in the radical (but in this case it's outside). You would fix this by just getting rid of the i entirely (and keeping the 2)

I'm not really too sure how you would do three but I'll give it a shot anyways

our equation will look like this: x²+2x

which means our quadratic equation would look like this

`(-2+/-√(2^2-4*1*0))/(2)\\=\\\\(-2+/-(2))/(2)\\\\\\= -1+/-(1)\\\\-1+1=0\\-1-1=-2`

When I write +/- I mean plus or minus giving us -2 and 0 as our solutions