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Reid's school is due west of his house and due south of his friend Eve's house. The distance between the school and Eve's house is 3 miles, and the straight-line distance between Reid's house and Eve's house is 5 miles. How far is Reid's house from school?

A. 4 miles
B. 2 miles
C. 6 miles
D. 8 miles

User Indolent
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1 Answer

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Final answer:

To find the distance between Reid's house and the school, we can use the concept of Pythagorean theorem. Reid's house is approximately 5.83 miles away from the school.

Step-by-step explanation:

To find the distance between Reid's house and the school, we can use the concept of Pythagorean theorem. Let's call the distance between Reid's house and the school 'x'. We know that the distance between Reid's house and Eve's house is 5 miles and the distance between the school and Eve's house is 3 miles.

We can form a right triangle with the straight-line distance between Reid's house and Eve's house as the hypotenuse. The distance between the school and Eve's house is one of the legs, and the distance between Reid's house and the school (which we are trying to find) is the other leg.

Using Pythagorean theorem, we have:

x^2 = (3^2) + (5^2)

Simplifying further:

x^2 = 9 + 25

x^2 = 34

Taking the square root of both sides:

x = sqrt(34) ≈ 5.83 miles

Therefore, Reid's house is approximately 5.83 miles away from the school.

User Scher
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