Final answer:
The frequency of the sound produced by a mosquito flapping its wings every 0.0080 seconds is 125 Hz, which is option A in the multiple-choice question presented.
Step-by-step explanation:
To calculate the frequency in Hertz (Hz) of the sound made by a mosquito that flaps its wings every 0.0080 seconds, you need to use the formula:
Frequency (f) = 1 / Period (T)
Where the period (T) is the time taken for one complete cycle, which in this case is the time taken for one flap of the mosquito's wings. Since we are given that T = 0.0080 seconds, we can calculate the frequency as follows:
f = 1 / T
f = 1 / 0.0080 s
f = 125 Hz
Therefore, the frequency of the sound produced by the mosquito flapping its wings is 125 Hz, which corresponds to option A.