Question

Find the zeros of the function below: g(x) = 3s^2 - 42a + 135.

a) x = 5
b) x = 9
c) x = 15
d) x = 45

Answer 1

To find the zeros of the function g(x) = 3s^2 - 42a + 135, rearrange the equation, factor it, and solve for s. The zeros are a) x = 5 and b) x = 9.

Step-by-step explanation:

To find the zeros of the function g(x) = 3s² - 42a + 135, we need to solve the equation 3s² - 42a + 135 = 0. Let's rearrange the equation:

3s² - 42a + 135 = 0

s² - 14a + 45 = 0

Now, we can factor the equation:

(s - 5)(s - 9) = 0

Setting each factor equal to zero gives us the zeros:

s - 5 = 0, therefore s = 5

s - 9 = 0, therefore s = 9

So, the zeros of the function g(x) are x = 5 and x = 9. Therefore, the correct options are a) x = 5 and b) x = 9.