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Given the point (-2, 2) and a slope of -4/7, what is the equation of the line in standard form?

a. 7x - 4y = -14
b. 4x - 7y = -14
c. 7x - 4y = 14
d. -4x + 7y = 14

User Splonk
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7.8k points

2 Answers

4 votes

Answer:

4x + 7y - 6 = 0

Step-by-step explanation:

b = y - m*x

2 - (-4/7)*(-2) = 2 - 8/7 = 6/7

y = -4/7x + 6 /7

4/7x + y - 6/7 = 0

7(4/7x + y - 6/7) = 0

4x + 7y - 6 = 0

User Jprim
by
8.4k points
4 votes

Final answer:

The correct answer for the equation of a line given the point (-2, 2) and the slope -4/7 in standard form is d. 4x + 7y = 14. This is derived by using the point-slope form and converting it to standard form.

Step-by-step explanation:

To find the equation of a line given a point and a slope, you can use the point-slope form of a linear equation and then convert it to standard form. The point-slope form is expressed as (y - y1) = m(x - x1), where (x1, y1) is the point and m is the slope of the line.

For the given point (-2, 2) and the slope -4/7, the point-slope form would be:

y - 2 = (-4/7)(x + 2)

Multiplying through gives:

y - 2 = (-4/7)x - (8/7)

Multiplying each term by 7 to eliminate the fraction and rearrange the terms to get the standard form, Ax + By = C, we get:

7y - 14 = -4x - 8

Adding 4x to both sides and adding 14 to both sides gives:

4x + 7y = 14

Therefore, the correct answer in standard form is: d. 4x + 7y = 14.

User Jorge Frias
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7.9k points