Final answer:
To find the grams of PbS that can be made from 80.0 g of Pb(NO3)2, we use the balanced equation, stoichiometry, and molar masses. First, we calculate the moles of Pb(NO3)2, then use the stoichiometric ratio to find the moles of PbS. Finally, we convert the moles of PbS to grams using the molar mass of PbS.
Step-by-step explanation:
To determine the number of grams of PbS that can be made from 80.0 g of Pb(NO3)2, we need to use the balanced equation for the reaction. The balanced equation is:
Pb(NO3)2 + H2S → PbS + 2 HNO3
According to the stoichiometry of the equation, 1 mole of Pb(NO3)2 reacts with 1 mole of H2S to produce 1 mole of PbS. We can calculate the moles of Pb(NO3)2 in 80.0 g using its molar mass:
80.0 g Pb(NO3)2 x (1 mole Pb(NO3)2 / molar mass of Pb(NO3)2) = X moles of Pb(NO3)2
Next, we can use the stoichiometric ratio to calculate the moles of PbS that can be formed:
X moles of Pb(NO3)2 x (1 mole PbS / 1 mole Pb(NO3)2) = X moles of PbS
Finally, we can convert the moles of PbS to grams using the molar mass of PbS:
X moles of PbS x (molar mass of PbS / 1 mole PbS) = X grams PbS