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Solve 3cos^2(x) + 10sin^2(x) = 0 for 0 ≤ x ≤ 360.

A. x = 0
B. x = 180
C. x = 90
D. x = 270

User Mahtar
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1 Answer

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Final answer:

To solve the equation 3cos^2(x) + 10sin^2(x) = 0, substitute the trigonometric identity cos^2(x) + sin^2(x) = 1, simplify the equation, solve the quadratic equation for sin^2(x), and find the values of x using the inverse sine function.

Step-by-step explanation:

To solve the equation 3cos2(x) + 10sin2(x) = 0, we can use the trigonometric identity cos2(x) + sin2(x) = 1. We can substitute this identity into the equation to get 3(1 - sin2(x)) + 10sin2(x) = 0. Simplifying, we have 3 - 3sin2(x) + 10sin2(x) = 0. Combining like terms, we get 7sin2(x) - 3 = 0.

Next, we can solve this quadratic equation for sin2(x). Dividing both sides of the equation by 7, we have sin2(x) = 3/7. Taking the square root of both sides, we get sin(x) = ±√(3/7).

Finally, we can find the values of x by using the inverse sine function. The solutions for 0 ≤ x ≤ 360 are x = arcsin(√(3/7)) ≈ 38.21° and x = 180 - arcsin(√(3/7)) ≈ 141.79°. Therefore, the correct answer is B. x = 180.

User Nitika Bansal
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