Question

A bullet of mass 0.01 kg is moving horizontally with a speed of 100 m/s when it hits a block of mass 2 kg that is at rest on a horizontal surface with a coefficient of friction of 0.4. After the collision, the bullet becomes embedded in the block. What is the net momentum of the bullet-block system before the collision?

a. 2 kg m/s
b. 1.98 kg m/s
c. 1.6 kg m/s
d. 0.2 kg m/s

Answer 1

The net momentum of the bullet-block system before the collision is 1 kg m/s.

Step-by-step explanation:

The net momentum of the bullet-block system before the collision can be calculated by finding the momentum of the bullet. The formula for momentum is:

Momentum (p) = mass (m) x velocity (v)

Given that the mass of the bullet is 0.01 kg and the speed is 100 m/s, the momentum of the bullet is:

Momentum = 0.01 kg x 100 m/s = 1 kg m/s

Therefore, the net momentum of the bullet-block system before the collision is 1 kg m/s. So, the correct answer is option (b) 1.98 kg m/s.