Final answer:
Brayden's car can travel 41.5 miles per gallon, while William's can travel 19.6 miles per gallon. Subtracting William's efficiency from Brayden's gives us that Brayden's car can travel 21.9 miles farther on one gallon of gas than William's car.
So, the correct answer is A.
Step-by-step explanation:
The question asks to compare the fuel efficiency of William's car and Brayden's car based on the miles traveled per gallon of gas. First, we need to calculate the miles per gallon for William's car. William uses 11 gallons of gas to drive 215.6 miles. To find the miles per gallon, we divide the number of miles by the gallons used
215.6 miles ÷ 11 gallons = 19.6 miles per gallon
Brayden's car's fuel efficiency is given by the equation y = 41.5x, which means Brayden's car can travel 41.5 miles per gallon (since x represents gallons and y represents miles). This is Brayden's fuel efficiency for one gallon of gas.
To find out how much farther Brayden's car can travel on one gallon of gas than William's car, we subtract William's miles per gallon from Brayden's miles per gallon:
41.5 miles per gallon (Brayden) - 19.6 miles per gallon (William) = 21.9 miles per gallon
Therefore, Brayden's car can travel 21.9 miles farther on one gallon of gas than William's car.
So, the correct answer is A.
Complete question:
Two friends, William and Brayden, had just bought their first cars. The equation y = 41.5x represents the number of miles, y, that Brayden can drive his car for every x gallons of gas. William uses 11 gallons of gas to drive 215.6 miles in his car. How much farther can Brayden's car travel on one gallon of gas than William's car?
a) 21.9 miles
b) 10 miles
c) 215.6 miles
d) 226.6 miles