Question

Before decomposing, these 20 moles of hydrazine are a liquid with a density of 1.02. The molecular weight of hydrazine is 32.0452. What is the volume of this mass of hydrazine before it decomposes in milliliters? Round your answer to the nearest hundredth.

a) 20 moles of hydrazine occupy a volume of [Answer] milliliters.
b) 20 moles of hydrazine occupy a volume of 20.40 milliliters.
c) 20 moles of hydrazine occupy a volume of 32.04 milliliters.
d) 20 moles of hydrazine occupy a volume of 1.02 milliliters.

Answer 1

To find the volume of 20 moles of hydrazine before it decomposes, divide the mass by the density. The volume is approximately 629.91 mL.

Step-by-step explanation:

To find the volume of 20 moles of hydrazine before it decomposes, we can use the density of hydrazine. Density is mass divided by volume, and we know the molecular weight of hydrazine is 32.0452. Since the density is given as 1.02, we can use the formula density = mass/volume to find the volume. Rearranging the formula, we have volume = mass/density. Plugging in the given mass of 20 moles (20 x 32.0452 = 640.904 g) and density of 1.02 g/mL, we can calculate the volume:

Volume = 640.904 g / 1.02 g/mL = 629.91 mL

Rounding to the nearest hundredth, the volume of 20 moles of hydrazine before it decomposes is approximately 629.91 mL.